[EM] Competitive Districting Rule (back on topic)
raphfrk at netscape.net
raphfrk at netscape.net
Fri Jul 28 05:53:32 PDT 2006
I was trying to think of a reasonable definition of the shape of a
district such that it would be "reasonably contiguous"
One possibility that occured to me was using the ratio of the length of
the border to the square root of the area
By using the sqrt, it doesn't matter the size. 2 shapes which are just
scaled versions of each other will give the same result.
Some examples:
Circle: sqrt(pi*r^2)/(2*pi*r) = 0.282 (I think this is the highest
possible)
Square: sqrt(a^2)/4a = 0.250
2:1 rectangle: sqrt(2*1)/6 = 0.236
3:1 rectangle: sqrt(3*1)/8 = 0.217
4:1 rectangle: sqrt(4*1)/10 = 0.200
5:1 rectangle: sqrt(5*1)/12 = 0.186
9:1 rectangle: sqrt(9*1)/20 = 0.15
A good threshold might be 0.2. This would allow districts with an
aspect ratio of 4:1 or less.
It would also make it alot harder to have dumbbell shaped districts
which are joined by a narrow channel. Two equal circles that are
touching wouldn't work.
sqrt(2*pi*r^2) / (4*pi*r) = 0.199
In fact, that is another good reason to use 0.2.
A circular district could have a "shooter" of length 1.29 times the
radius (0 area but just adds to the border length). However, this
would also mess up the neighbouring district(s), which would then end
up having to be circular too.
The rule would be something like "the length of the border of a
district shall not be more than five times the square root of the area
of the district"
More information about the Election-Methods
mailing list