proof: 1:A>B>C 1:B>C>A 1:C>A>B symmetric cycle and 3-way tie (assuming anonymity & neutrality) so 1/3, 1/3, 1/3 victory probabilities. Now if the C>A>B voter changes to C>B>A, this makes B the condorcet winner (100% victory probability if condorcet mathod) so the "later" choice of B>A rather than A>B "harmed" C. QED wds