[EM] Ranked Pairs tiebreaker scheme

[Eric Gorr]

Kevin Venzke wrote:
> Hello,
> 
> Is this Ranked Pairs tie-breaking method usable?:
> 
> "Suppose A>B and C>D are of equal strength as strength is being defined.
> 
> If B is not D and one of B and D defeats the other pairwise, then rank
> A>B ahead of C>D if D defeats B, or vice versa if B defeats D.
> 
> Else (when B is D, or B and D tie pairwise) rank A>B ahead of C>D if A
> defeats C pairwise, and C>D ahead of A>B if C defeats A pairwise."

Looks interesting.

What would you do if neither A nor C defeat the other pairwise?