[EM] EM] recommendations (single-winner)
Chris Benham
chrisbenham at bigpond.com
Thu Sep 2 22:52:09 PDT 2004
Participants / anyone interested,
In my opinion, the most important/serious category of single-winner
method is
(1) plain rankings-ballot methods in which voters are asked to simply
rank the candidates. Truncation should be allowed, and allowing equal
non-last ranking is desirable but perhaps not absolutely essential.
Methods that ask voters to rank only those candidates they approve,
although the ballots look the same, are hybrid Approval/
limited-rankings methods and in my view are in a different (much less
desirable) category.
The other category I favour is
(2) high-resolution ratings ballots, with many more available slots
than there are candidates, so that rankings can be inferred from ratings.
In this category my current favourite is "Automated-Approval Margins"
(AAM), a Condorcet-completion method.
Inferring rankings from the ratings, eliminate (and henceforth
completely ignore) the non-members of the Schwartz set.
If more than one candidate remains, then each ballot approves the
candidates they rate above average (the arithmetical mean of the
Schwartz-set candidates) and half-approves those they rate exactly
average. The (inferred) rankings are used to determine the results
of the pairwise comparisons, but the margins between the (derived)
"automated" approval-scores are used to weigh these results
(the strengths of the "defeats"). On this basis pick the Ranked Pairs
winner . (I may later decide that something other than RP is
slightly better for the last step, but in practice it would very rarely
give a different winner).
Schwartz // SC-WMA.
My current favourite single-winner plain ranked-ballot method is
Schwartz // SC-WMA. "SC-WMA" stands for
"Symetrically Completed- Weighted Median Approval". I think it is
probably impossible for Smith // SC-WMA to ever give a
different result. (In Woodall terms, that would be "CNTT, SC-WMA"
with "CNTT" standing for "Condorcet(Net) TopTier").
Voters rank the candidates, truncation ok. Non-last equal prefernces
also ok. (If these are not allowed, compliance with the
Non-Drastic Defense criterion is lost, but the method is still good and
may be more of a practical propsition).
Eliminate the non-members of the Schwartz set (and henceforth continue
as though they had never stood).
Symetrically complete the ballots.
Now apply the "Weighted Median Approval" method to pick the winner.
Each (remaining) candidate is assigned a "weight" which is equal to the
number of first-prefernces they get. The sum of the "weights"
is equal to the total number of non-empty ballots.
Each ballot approves the candidate they rank in first-place. If the
weight of candidates so far approved by a ballot sums to less than half
the total weight of all the candidates, then that ballot also approves
the candidate they rank second..
And so on until each ballot has approved at least half the candidates
"by weight".
The candidate with the highest total (thus derived) approval score wins.
This would only very rarely be anywhere near as complicated as it might
appear. Usually there will be easy short-cuts. For example,
if the Schwartz set contains three members, then in practice that means
that each ballot approves the candidates they rank first and second;
and those which only rank one candidate, approve that candidate and
half-approve the other two.
The justification of this method is that unlike Winning-Votes, it
meets the Sincere Expectation Criterion. There is no silly zero-information
random-fill incentive. Unlike Margins, it meets Minimal Defense,
Non-Drastic Defense and Truncation Resistance.
Also, unlike Margins, it meets Woodall's Plurality and Weak
Independence of Irrelevant Alternatives criteria.
Unlike WV, it meets Woodall's Symetric Completion criterion. Unlike
MAM, it meets Independence of Pareto-Dominated Alternatives.
Also it is independant of any losers who are no voters' most preferred
Schwartz-set member.
The method, unlike Bucklin or QLTD, meets Clone Independence.
The (IMO) small price that is paid for all this is that unlike MAM, the
method fails Immunity from Majority Complaints; and the method
can fail Mono-raise when there are more than three candidates in the
Schwartz set.
35:BA/CD
30:CD/BA
05:CA/DB
15:AC/DB
15:DB/AC
A wins. Replace 5 CADB with 5 ACDB ballots gives:
35:BA/CD
30:CDB/A
20:AC/DB
15:DB/AC
Now A loses, violating Mono-raise.
In the above examples, all the candidates are in the Schwartz set, and
each ballot approves the candidates before the slash.
Chris Benham
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