[EM] "Leader of the Free World" Project

[Kevin Venzke]

Markus,

 --- Markus Schulze <markus.schulze at alumni.tu-berlin.de> a écrit : 
(Tengvall description moved to the bottom)

I think you may have misunderstood Tengvall's method:

> In short: The Tengvall winner is that Schwartz winner A whose
> worst pairwise comparison with another candidate B (measured
> by the absolute number of voters who strictly prefer candidate B
> to candidate A) is minimal.

I believe it is rather: that Schwartz winner A whose worst pairwise comparison
with another candidate B (measured by the absolute number of voters who strictly
prefer candidate *A* to candidate *B*, plus the number of voters ranking them
equal) is *maximal*.

If I've understood Tengvall correctly, these ballots:

49 A
24 B
27 C>B

produce a B-C tie.

Scores: A:B 49:51, A:C 73:51, B:C 73:76

Seems something is lacking here.  Tengvall should be alerted.


Kevin Venzke
stepjak at yahoo.fr


> > 1. Count votes in all pairwise comparisons, according to this:
> > Count a vote to X from every ballot where X is given better or
> > equal preference than Y, and to Y from every ballot where Y is
> > given better or equal preference than X. X beats Y if the former
> > score is bigger than the latter, and vice-versa.
> >
> > 2. The vote minimum of each X is the smallest score of X in any
> > of X:s comparisons.
> >
> > 3. There is a beatpath from X to Y if X beats Y (in pairwise
> > comparison between these two) or X beats some Z that beats Y.
> >
> > 4. Eliminate every candidate X such that there is a beatpath
> > from some Y to X but not vice-versa.
> >
> > 5. Check the vote minimum of each non-eliminated. The winner
> > is the one with the biggest vote minimum. (A tie is possible.)


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