# [EM] Martin Harper's "Majority Potential" Idea Applied to Social Orderings

Forest Simmons fsimmons at pcc.edu
Tue Apr 22 16:15:02 PDT 2003

```Actually, the credit should go to Richard Moore for the "Majority
Potential" idea.

Martin Harper was on my mind because (in that same epoch) he made a great
contribution called "Universal Approval" which considered all subsets of
candidates rather than all permutations of candidates.  Because these two
contributions were at about the same time and both Martin and Richard are
great Approval advocates, it wasn't too hard for my puny memory to make

Forest

On Tue, 22 Apr 2003, Forest Simmons wrote:

> The following is Martin Harper's "Majority Potential" idea adapted to
> the purpose of finding a "social ordering" by applying his idea to "order
> space" instead of issue space, which was the original context.
>
> Suppose that we have a set M of marked fully ranked preference ballots of
> the type contemplated for use with IRV, Borda, or Condorcet.  For now,
> let's say that neither equal ranking nor truncation is allowed.
>
> Now we want to make an head-to-head comparison between two social
> orderings  Order1 and Order2, to see which of the two orders better
> represents the set M of individual orderings.
>
> There are many ways to do this comparison.  But for now suppose that we
> have some way of measuring distance between permutations (i.e. orderings)
> of the candidates.
>
> There are many ways of measuring distance between orderings.  For
> definiteness let us focus on the Kemeny distance, which is the minimum
> number of transpositions required to convert one order (of a pair) into
> the other.
>
> There are many ways to make head-to-head comparisons using this distance.
> For example, we could follow Kemeny's lead and say that Order1 beats
> Order2 if and only if the sum of the distances from members of M to Order1
> is smaller than the sum of distances to Order2.
>
> But let's follow Martin Harper's majority idea instead of Kemeny's idea,
> i.e. let's take the Harper fork in the road rather than the Kemeny fork:
>
> We'll say that Order1 beats Order2 if and only if the number of members of
> M that are closer to Order1 than to Order2 is greater than the number of
> members of M that are closer to Order2 than to Order1.
>
> In other words, among those members of M that have a preference (measured
> by the Kemeny distance), the majority prefer the first order over the
> second order.
>
> Now that we have a way of making head-to-head comparisons between social
> orderings, let us construct the pairwise margins matrix.  The entry in the
> i_th row and j_th column is the number of orderings in M that prefer
> Order_i over Order_j.
>
> Note that if there are N candidates there are N! permutations of the
> candidates, so this pairwise matrix has N!*N! entries.
>
> There are many possible ways of using this pairwise matrix, but let's
> follow Martin Harper's suggestion and go with the Copeland winner.
>
> In other words, the order with the greatest difference between the number
> ordering.
>
> [End of description of method.]
>
> Remarks:
>
> (1) If we had followed the Kemeny fork in the road, this Copeland winner
> would be identical to the Kemeny social ordering.
>
> (2) As Martin Harper pointed out long ago, the usual defects of Copeland's
> uniformly distributed.
>
> (3) Martin's idea can be adapted to create another Condorcet flavored
> Proportional Representation method, about which I will say more later.
>
> comparisons.  In general there are (N!-1)*N!/2 comparisons, so the method
> is not intended for use in public elections.
>
>
> Forest
>
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```