# [EM] Half Eliminations- Legislative body votes

DEMOREP1 at aol.com DEMOREP1 at aol.com
Wed Jan 2 22:08:34 PST 2002

```In cases where there is no time or technology to do Condorcet head to head
math in legislative bodies one somewhat quicker method is to eliminate a half
(or near half) of the choices at a time.

The combinations just above the dotted lines would be done.  *NO choice* (aka
None of the Above -- NOTA) would be a choice.

The remaining choices would repeat the procedure down to 1 versus 1.

Obviously with 3 or more choices there may be a divided majority and with 4
or more choices there also may be a divided minority.

Choices
Groups

2    1    1
-----------
3    2    1
-----------
4    3    1
2    2
-----------
5    4    1
3    2
-----------
6    5    1
4    2
3    3
-----------
7    6    1
5    2
4    3
-----------

Thus for example- in the 7 case, 3 would lose, then 2 of the 4 would lose and
then 1 of the 2 would lose.

Most legislative issues are somewhat independent so I doubt that even a 4
choice case would happen often.

For the filling of blanks by numbers (such as tax rates or the number of
local police), medians can be used.

```