[EM] Plausible IRV example showing non-monotonicity
Bart Ingles
bartman at netgate.net
Sat Mar 10 00:38:58 PST 2001
Here is a more-or-less plausible example showing both the no-show
paradox and a monotonicity violation in an IRV election. You could
think of the added/changed votes as being the result of either absentee
ballots, or of a recount (possibly including discovery of mislabeled
ballot containers, as happened in New Mexico).
This assumes the usual one-dimensional issue space, with the centrist
voters evenly split over their 2nd choice:
votes candidates (in order of preference)
----------------------------------------------
900 A B C
300 B A C
300 B C A
575 C B A
After C is eliminated, B wins 1175 to 900.
Next, add an additional 50 "absentee" votes for C:
50 C B A
Now C has 625 first-choice votes, eliminating B. C loses the 2nd round,
with 925 votes to A's 1200. The additional C voters would have been
better off staying home -- a no-show paradox. By voting, the C voters
helped elect their least favorite candidate.
Finally, suppose the absentee ballots were miscounted, and a recount
awards them all to A:
50 A C B
C is once again eliminated first, and B wins 1175 to 950. Giving the 50
votes to A causes A to lose -- a very plausible monotonicity violation.
The above was adapted from Fishburn's 7-6-5 example. The main thing I
wanted to add was a realistic centrist vote, with split 2nd choices.
The only thing remotely unusual about the election is the fact that B
and C are in a close race for 2nd place (in the first-round tally).
Bart Ingles
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