Methods of elimination in quota preferential STV

[Bart Ingles]

DEMOREP1 at aol.com wrote:
> 
> Mr. [Ingles] wrote in part-
> 
> Voters simply vote for multiple candidates, as they would with approval
> voting, except that each choice gets an equal fraction of the vote (e.g.
> if you vote for five candidates, each gets 1/5 of your vote).  You then
> eliminate the weakest candidate and recount, so that the remaining
> candidates get a larger share (if one candidate was eliminated from your
> ballot, the remaining candidates now each get 1/4 of a vote).  Continue
> eliminating candidates in the same fashion until the required number
> remain.
> ----
> D- As with Approval Voting with single winners, the A=B=C notion is false in
> most cases.

What is 'the A=B=C notion'?


> However, it is simple (but probably requiring computerized elections due to
> the fractions).
> 
> A possible minor problem with the end result-
> 
> 3 member legislative body
> 
> winners and their votes
> 
> A       B       C
> 
> N1     N1     N1  (1/3 votes)
> N2     N2           (1/2 votes)
>          N3     N3  (1/2 votes)
> N4              N4  (1/2 votes)
> N5                     (1 vote)
>         N6             (1 vote)
>                   N7   (1 vote)
> 
> Would each winner have a voting power in the legislative body equal to the
> votes he/she receives ???

I'm not sure what is being shown in the above example.  Are A, B, and C
the candidates, and N1-7 the voters?

If instead you meant to show a 7-way tie, then it would need to be
resolved in the same way as any other system. 

Bart