YES versus Head to Head Tiebreakers
DEMOREP1 at aol.com
DEMOREP1 at aol.com
Thu Apr 13 12:55:07 PDT 2000
Applying the original posting in a 2 member district p.r. election (with 2
distinct groups that just happen to have circular ties)-
YES votes [ONLY] Max YES for 1st choices
123
22 ABC 61
21 BCA 61
18 CAB 61
14 FGH 39
13 GHF 39
12 HFG 39
100
No head to head winners
Droop = 34
1+2 1+2+3 Final (Voting powers)
A 40 0 0
B 43 43 61 B gets the most the earliest
C 39 18 0
F 26 39 0
G 27 39 0
H 25 39 39 (wins lottery tie)
In other words there are the 3 matrices going on--
YES matrix
1 2 3 4 etc. Total YES
A A1 A2 A3 A4 etc AT
B B1 B2 B3 B4 etc. BT
C etc
Head to head matrix
A B C etc
A X A/B A/C etc
B B/A X B/C etc.
etc.
Accumulated YES matrix (high to low in each column)
1 1-2 1-3 etc.
B1 C12 D13 etc.
C1 D12 F13 etc.
A1 F12 B13 etc.
etc. etc. etc.
Thus,
1. Vote YES/NO [from me derived from Approval and standard issue elections]
and number votes [from Condorcet].
2. Do head to head [from Condorcet].
3. If less than N head to head winners, then accumulate the YES position
votes to get a Droop quota [from Bucklin and applying number voting to
Approval] (i.e. an earlier YES ranks more than a later YES).
For proportional representation elections, there probably should also be a
separate YES/NO and Numbers vote for Parties/Independents (as a party group)
for the apportioning of the Droop quotas to get seats (using the method of
equal proportions).
As usual- minorities which can not get a Droop quota would be wise to vote
YES on additional choices in order to have some influence on the results.
That is- if the above was for a single winner office, then the F, G and H
first choice voters may also want to vote YES for the lesser perceived evil
of A, B or C.
More information about the Election-Methods
mailing list