[EM] YES/Number Votes Method

DEMOREP1 at aol.com DEMOREP1 at aol.com
Sun Sep 26 19:39:49 PDT 1999


For simpler tiebreaker purposes there is the following --

Summary -

A. Vote YES/NO on each choice and rank the choices using number votes (1, 2, 
etc.) or use a scale vote such as 0 to 100 with 51 or more being deemed a YES 
vote).  Using scale votes would show that many winners may not be especially 
popular.

B. Executive and Judicial offices (1 or more positions) - Two or more choices 
getting YES majorities go head to head using the number votes.
Legislative bodies - Both parties and individual candidates would go head to 
head. 

Head to head involves doing all of the combinations of Test Winner(s) versus 
Test Loser (with other choices being deemed Other Test Losers).  It would 
generally require a computer to do all of the math in a large election.

C. If head to head fails to fill all positions, then drop the choice with the 
lowest number of YES votes and recheck the head to head math for the 
remaining position(s).

D. Legislative body winners would have a voting power equal to the number of 
votes finally received (first choice votes plus transferred votes from 
losers) (i.e. No STV type fractional transfer votes math to worry about.)
---
For a single winner office I note again that simple Approval Voting (vote 1, 
X or YES for a choice) is defective since a first choice majority may lose.

51 A B
49 B
B wins using simple AV

That is, simple AV is defective because it fails to rank choices and have 
them go head to head.
--
Even the simple 3 choice case is rather complex ---

YES votes

A
AB
AC
ABC
ACB
B
BA
BC
BAC
BCA
C
CA
CB
CAB
CBA

That is, there are 15 possible types of YES votes with the simple summary 
matrix --

  Place Vote

1    2    3   Total

A1  A2   A3   AT
B1  B2   B3   BT
C1  C2   C3   CT

For legislative bodies - If a party gets N Droop Quotas, then it would get N 
seats.

Using the lowest YES votes as a tiebreaker would replace having to look at 
worst head to head defeats.



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