FPTP family theory, REDLOG shadowing

[DEMOREP1 at aol.com]

I repeat my observation about clones-

34 A>B>C
33 B>C>A
32 C>A>B

99

Circular tie
A>B>C>A

Adding D-- a 100 percent clone of B

34 A>B>D>C
33 B>D>C>A
32 C>A>B>D

A>B>D>C>A

Going backwards, even the simple 3 choice example above can be deemed to have 
a lurking clone.  Namely, the worst defeated choice is the most likely 
(probable) clone.

Thus, the same applies with any N >2 case and technically even the simple N=2 
case.  Whether the amount of "cloneness" is the same (100 percent) or nearly 
half (just short of a tie) does not matter.

Public elections are for real and not some higher math exercise to be 
repeated with more or less candidates and more or less voters.

Many criteria floating around are totally irrelevant to real elections for 
real candidates by real voters.