50-49 Tie

[DEMOREP1 at aol.com]

Yet another Condorcet circular tie--
48 AC
1   AB

48 B

1 CA
1 CB

50 A > 49 B
50 B > 49 C
50 C > 49 A
Does common sense say which candidate (and his/her voters) should lose to
resolve the tie ?

C should lose and his/her 2 first choice supporters.  The reason- the lowest
number (i.e. smallest minority) of voters should have to drop their first
choices to resolve the tie.

Thus A should win.

The circular tie breaker applies in like manner with 4 or more candidates in
the circular tie and then redoing the head to head math.