Eye Ball Mathematics
DEMOREP1 at aol.com
DEMOREP1 at aol.com
Sat Nov 16 18:52:55 PST 1996
Donald- My question is: How do we know which candidate is the indicated
majority candidate?
46ABC
20B
34CBA
Demorep1- Head to head pairings in the example produces-
A vs. B
46ABC 46
20B[A=C] 20
34CBA 34
46 54
---
B vs. C
46ABC 46
20B[A=C] 20
34CBA 34
66 34
---
C vs. A
46ABC 46
20B[A=C]
34CBA 34
34 46
B > A
B > C
A > C
B wins by beating each head to head.
---
Donald- In Steve's example I can eye ball the example and I can tell in my
mind that B has a majority of the choices within the first two selections -
but with a larger example I would not be able to know by eye balling - I will
need some mathematics.
My next question is: What are the mathematics of eye balling?
--
Demorep1- With even 3 candidates, it is easy to make errors with eye balling.
Do the results on paper and not in your mind.
--
Donald- When I eye ball I am adding the choices of the same candidate
together - but it occured to me that what I am doing is Approval Voting. Is
Approval Voting the mathematics being used when we determine the majority
rule candidate?
--
Demorep1- If no candidate beats each other candidate in head to head
pairings, then there must be a tie breaker. Approval voting could be a tie
breaker.
--
Donald- Also - why do we add the choices of only the first two selections?
Why not add all three selections?
--
Demorep1- In a more complex example (such as having 5 candidates) all the
rankings would have to added, not just the first two choices or three
choices. Part of this is semantics. That is, the uses of "choice" and
"selection". There is no need to use "selection(s)".
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