[Election-Methods] How is the Nanson and/or Baldwin non-monotonic?
Chris Benham
chrisjbenham at optusnet.com.au
Thu Sep 20 13:31:23 PDT 2007
John Wong wrote:
> How is the Nanson and/or Baldwin non-monotonic? I've been trying to
> develop an example where they are non-monotonic, but I'm having trouble.
>
I think this is an example of Borda Elimination (Baldwin?) failing
mono-raise.
31: A>B
32: B>C
03: A>C
31: C>A
03: C>B
Borda scores: C103, A99, B98.
Eliminate B, and C wins.
Now change the 3 A>C ballots to C>A (i.e. do nothing but raise C on some
ballots without changing any rankings
among other candidates).
31: A>B
32: B>C
03: C>A
31: C>A
03: C>B
Borda scores: C106, B98, A96.
Eliminate A, and B wins.
Note that this doesn't work for (original?) Nanson, because that elects
C both times (because both times A and B have
below average Borda scores and so are eliminated).
Here is a demonstration from Douglas Woodall that that method fails
mono-raise:
> dabc 40 Borda scores: a 154 average Borda score 150
> bcad 26 b 152
> cabd 24 c 154
> cdba 10 d 140
>
> With the profile as given, only d is excluded, which results in
> abc 40 Borda scores: a 104 average Borda score 100
> bca 26 b 102
> cab 24 c 94
> cba 10
> Now c is excluded and a wins. But if the ten cdba ballots in the
> original profile are replaced by cdab, then the Borda scores become
> a 164, b 142, c 154, d 140, so that b and d are both excluded and c wins.
>
John Wong wrote:
> How nonmonotonic is Nanson/Baldwin Method?
John,
The normal meaning of "monotonic" is that it meets the mono-raise
criterion, a binary yes-no test. Woodall has other
"monotonicity" criteria/properties. Your question can be interpreted in
more than one way.
http://groups.yahoo.com/group/election-methods-list/files/wood1996.pdf
http://wiki.electorama.com/wiki/Monotonicity_criterion
Chris Benham
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