[EM] Cloneproof SSD

[Markus Schulze]

Dear Mike,

you wrote (21 Jan 2001):
> When we randomly choose a tiebreaking
> ballot, the members of the C clone set, no matter how many of them
> there are, are no more likely to be at the top of that ballot than
> A & B are. A, B, and the C clone set are equally likely to be at the
> top of that tiebreaking ballot, as they should be. Adding those C
> clones hasn't increased the probability of the winner being a C clone.

It isn't clear to me how you use random ballot to decide which
pairwise defeat you drop.

Example: Suppose that you have to decide whether W:X or Y:Z is dropped.
Suppose that the randomly chosen ballot is W > Y > X > Z. How does this
randomly chosen ballot helps you to decide which pairwise defeat should
be dropped?

Markus Schulze