50-49 Tie -- Math Correction

[DEMOREP1 at aol.com]

I thank a reader for pointing out that the A, B, C math does not produce the
indicated result.
The math in the example should have been

47 AC
2   AB

48 BC

1 CA
1 CB

50 A > 49 B
50 B > 49 C
50 C > 49 A

Generally for 3 candidate examples one should draw a circle and add the
numbers along the arc for a given candidate (such as N1 AB, N2 A (no second
choice), N3 AC) to produce and check the possible results. 

                .     .
         .                 .     B
     .                         .
A .                              .
   .                              .
     .                         .
        .                  .
              .        .
                  C
------
                            
   2 AB     .     .   0 BA
        .                 .     
     .                         .    48 BC
   .                              .
   .                              .
     .                          .    
 47     .                  .       
  AC         .        .     1 CB
           1 CA