Numbers of Truncations
DEMOREP1 at aol.com
DEMOREP1 at aol.com
Tue Nov 19 19:06:38 PST 1996
Due to the large number of truncation possibilities in rank voting (1, 2,
etc.), creating "real" examples on paper is labor intensive.
3 Candidates
vote 1 3 possibilities
vote 2 3 X 2= 6 possibilities
vote 3 3 X 2 x1 = 6 possibilities (this is the same as the AB line since
the last choice can defeat no one)
Total 15
4 Candidates
vote 1 4
vote 2 4 x 3 = 12
vote 3 4 x 3 x 2 = 24
vote 4 same 24
Total 64
5 Candidates
vote 1 5
vote 2 5 x 4 = 20
vote 3 5 x 4 x 3 = 60
vote 4 5 x 4 x 3 x 2 = 120
vote 5 same 120
Total 325
Any math majors in stats who can produce the general formula?
For simulation purposes (as if all the votes were sorted into the
possibilities), the candidates can be numbered (e.g. a vote that is DBECA
would be 4-2-5-3-1 in five columns on a spreadsheet).
With the use of multiple IF functions the votes can be summed.
Example- If the value in column 3 is 5 and if the value in column 4 is 3,
then candidate 5 gets a vote in the 5 v. 3 comparison.
Many spreadsheet programs can directly convert letters to numerical values.
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